Integrating the time as a function of radius
Now let's calculate the time dependence. The same trick of dividing by the
"dot" (dt ~ (tdot/rdot) dr) can be used. We can get away with only
using rdotin[r] and not rdotout[r] because we'll be losing that sign difference
again later:
In[125]:=
dt[r_] = tdot[r]/rdotin[r]
Out[125]=
1
-(---------------)
2
b
Sqrt[1 - -----]
2 2
c r
Now we integrate to find the time, using the parameter t0 for the time at which
r = b/c:
In[126]:=
t[r_] = t0 + Integrate[dt[r],r]
Out[126]=
2 2 2
-b + c r
-(r Sqrt[-----------]) + t0
2 2
c r
This relationship can be inverted so the radial coordinate r can be expressed
in terms of coordinate time t:
In[127]:=
tsq = t[r]^2
Out[127]=
2 2 2
-b + c r 2
(-(r Sqrt[-----------]) + t0)
2 2
c r
Now solve for r[t]:
In[128]:=
R = Solve[tsq == t^2, r]
Out[128]=
2
b 2 2
{{r -> -Sqrt[-- + t - 2 t t0 + t0 ]},
2
c
2
b 2 2
{r -> Sqrt[-- + t - 2 t t0 + t0 ]}}
2
c
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