Solve the equations for the velocities
To solve our system of equations, we use the Mathematica function
Solve[]:
In[96]:=
eqrules = Solve[eqlist,{rdot[r],thdot[r],tdot[r]}]
Out[96]=
2
2 J
{{rdot[r] -> -Sqrt[E - -----], tdot[r] -> E,
2 2
c r
2
J 2 J
thdot[r] -> -----}, {rdot[r] -> Sqrt[E - -----],
2 2 2 2
c r c r
J
tdot[r] -> E, thdot[r] -> -----}}
2 2
c r
Now we face a sign choice for our path. The derivative rdot[r] can be positive
(travelling away from the central mass as time increases) or negative
(travelling towards from the central mass as time increases).
So we'll make two functions, one for incoming and one for outgoing geodesics:
In[97]:=
rdotin[r_] = rdot[r] /. eqrules[[1]][[1]]
Out[97]=
2
2 J
-Sqrt[E - -----]
2 2
c r
In[98]:=
rdotout[r_] = rdot[r] /. eqrules[[2]][[1]]
Out[98]=
2
2 J
Sqrt[E - -----]
2 2
c r
In[99]:=
thdot[r_] = thdot[r] /. eqrules[[1]][[3]]
Out[99]=
J
-----
2 2
c r
In[100]:=
tdot[r_] = tdot[r] /. eqrules[[1]][[2]]
Out[100]=
E
The energy and angular momentum of a photon's trajectory around the central
point mass can be absorbed into the "impact parameter", which measure
the distance of closest approach to the point mass. The impact parameter is the
ratio b = J/E, or angular momentum per unit energy. Notice that a photon
trajectory with zero angular momentum relative to the central point mass has
zero impact parameter. This is correct, because it's just a direct path to the
point mass! The distance of closest approach is zero.
We institute this reparametrization as follows:
In[101]:=
paramrules = {E -> 1, J -> b}
Out[101]=
{E -> 1, J -> b}
In[102]:=
rdotout[r_] = rdotout[r] /. paramrules
Out[102]=
2
b
Sqrt[1 - -----]
2 2
c r
In[103]:=
rdotin[r_] = rdotin[r] /. paramrules
Out[103]=
2
b
-Sqrt[1 - -----]
2 2
c r
In[104]:=
thdot[r_] = thdot[r] /. paramrules
Out[104]=
b
-----
2 2
c r
In[105]:=
tdot[r_] = tdot[r] /. paramrules
Out[105]=
1
Up to Compute and solve the equations for light propagation
|