Compute the equations for the velocities
The geodesic equation can be written either as a second-order differential
equation for the spacetime position of the test particle as a function of proper
time -- or as a first order differential equation for the spacetime velocity of
the test particle as a function of proper time.
But remember -- right now we're looking for how light travels in this
spacetime. A ray of light travels like a test particle of zero mass, and test
particles of zero mass don't have a "proper time" defined
for them. (Because light goes at the speed of light, which is never zero, hence
there is no "rest frame" for a massless particle where proper time can
be measured.) Instead there is a proper "affine parameter" that
measures the distance along a lightlike curve through spacetime.
The easiest way to solve the geodesic equations is to start by defining the
spacetime velocity vector, or the geodesic tangent vector as mathematicians call
it. The "dot" below refers to the derivative with respect to the
proper affine parameter v, but it turns out we can solve for the geodesics
without ever having to use the proper affine parameter explicitly. We do this
through mathematical trickery explained below.
In[76]:=
DefineTensor[U,"U",{{1},1}]
PermWeight::def: Object U defined
In[77]:=
U[1] = rdot[r]
U[2] = thdot[r]
U[3] = tdot[r]
Out[77]=
rdot[r]
Out[78]=
thdot[r]
Out[79]=
tdot[r]
In[80]:=
U[la_] = MakeSum[Metricg[la,lb] U[ub]]
Out[80]=
g rdot[r] + g tdot[r] + g thdot[r]
1a 3a 2a
In[81]:=
U[-1]
Out[81]=
rdot[r]
In[82]:=
U[-2]
Out[82]=
2 2
(1 - 4 G M) r thdot[r]
In[83]:=
U[-3]
Out[83]=
-tdot[r]
Now it's time for the mathematical trickery! We will take advantage of the
symmetry of this problem to skip several steps. We wind up in the end with three
equations to solve. The first equation we get from wanting the paths of photons.
This means that the vector U[ua] squares to zero. We'll also absorb the factor
of (1 - 4GM) into the single parameter c:
In[84]:=
eqn1 = Simplify[MakeSum[U[ua] U[ub] Metricg[la,lb]]] == 0
/. (1 - 4 G M) -> c
Out[84]=
2 2 2 2 2
rdot[r] - tdot[r] + c r thdot[r] == 0
The second and third equations give us our constants of motion for the paths we
seek, from the metric "dot product" of each basis Killing vector with
the tangent vector to our geodesic. The first Killing basis vector is in the t
direction, and the constant of motion it determines is the energy of the photon.
In[85]:=
DefineTensor[Kt,"Kt",{{1},1}]
PermWeight::def: Object Kt defined
In[86]:=
Kt[1] = 0
Kt[2] = 0
Kt[3] = 1
Out[86]=
0
Out[87]=
0
Out[88]=
1
In[89]:=
eqn2 = Simplify[MakeSum[Kt[ua] U[ub] Metricg[la,lb]]] == -E
Out[89]=
-tdot[r] == -E
The third equation sets the second constant of motion, which is the angular
momentum of the photon around the point mass M:
In[90]:=
DefineTensor[Ktheta,"Ktheta",{{1},1}]
PermWeight::def: Object Ktheta defined
In[91]:=
Ktheta[1] = 0
Ktheta[2] = 1
Ktheta[3] = 0
Out[91]=
0
Out[92]=
1
Out[93]=
0
In[94]:=
eqn3 = Simplify[MakeSum[Ktheta[ua] U[ub] Metricg[la,lb]]] == J
/. (1 - 4 G M) -> c
Out[94]=
2 2
c r thdot[r] == J
Now we just solve the system of equations for rdot, thdot and tdot:
In[95]:=
eqlist = {eqn1, eqn2, eqn3}
Out[95]=
2 2 2 2 2
{rdot[r] - tdot[r] + c r thdot[r] == 0,
2 2
-tdot[r] == -E, c r thdot[r] == J}
Up to Compute and solve the equations for light propagation
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